Draw ∆ ABC in which AC = 6 cm, ∠A = 90° and ∠B = 60°.

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Solution

We can see that ∠A+∠B+∠C = 180°. Therefore ∠C = 180 $°$ − 60 $°$ − 90 $°$ = 30°.

Steps of construction:

Draw a line segment AC = 6 cm.

Draw $∠ A C X = 30 °$ .

Draw $∠$ CAY with Y on the same side of AC as X such that $∠$ CAY = 90 $°$ .

Join CX and AY. Let these intersect at B.

ABC is the required triangle where angle $∠$ ABC = 60 $°$ .

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