Question

Draw $∆$ABC in which BC = 6 cm, AC - AB = 2 cm and $\angle$C - $\angle$B = 30$°$

Answer 1

Steps of construction:
1. Draw BC = 6 cm.
2. Draw ray BX, such that $\angle \mathrm{CBX}=15°\left(\mathrm{i}.\mathrm{e}.\frac{\angle \mathrm{C}-\angle \mathrm{B}}{2}\right)$.
3. With C as centre and radius 2 cm, draw an arc intersecting ray BX at point S.
4. Join C and S and produce CS.
5. Draw the perpendicular bisector of seg BS. Let it intersects CS(extended) in A.
7. Join A and B.
8. Hence, $△$ABC is the required triangle.