Draw ∆ ABC in which BC = 8 cm, ∠B = 50° and ∠A = 50°.

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Solution

$∠ A B C + ∠ B C A + ∠ C A B = 180 ° ∠ B C A = 180 ° - ∠ A B C - ∠ C A B ∠ B C A = 180 ° - 100 ° = 80 °$

Steps of construction:

Draw a line segment BC of length 8 cm.

Draw $∠ C B X such that ∠ C B X = 50 °$ .

Draw $∠$ BCY with Y on the same side of BC as X such that $∠$ BCY = 80 $°$ .

Let CY and BX intersect at A.

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