Question

Draw an electron dot structure for ${Br}_3^{-}$. Deduce an approximate value of the bond angle.

Answer 1

In ${Br}_3^{-}$, total number of valence electrons $=7\left(3\right)+1=22$.

In this the center $Br$ has expanded octet. After bonding with other two $Br$, number of valence electrons in center $Br$ will be 10.

The shape of ${Br}_3^{-}$ is linear. So, its bond angle will be equivalent to 180 degrees.