Question

Draw formulas for the first five members of each homologous series beginning with the following compounds. (a) H–COOH (b) CH₃COCH₃ (c) H–CH=CH₂

Answer 1

The first five members of each homologous series beginning with the given compounds are shown as follows:

(a)

H–COOH : Methanoic acid

CH₃–COOH : Ethanoic acid

CH₃–CH₂–COOH : Propanoic acid

CH₃–CH₂–CH₂–COOH : Butanoic acid

CH₃–CH₂–CH₂–CH₂–COOH : Pentanoic acid

(b)

CH₃COCH₃ : Propanone

CH₃COCH₂CH₃ : Butanone

CH₃COCH₂CH₂CH₃ : Pentan-2-one

CH₃COCH₂CH₂CH₂CH₃ : Hexan-2-one

CH₃COCH₂CH₂CH₂CH₂CH₃ : Heptan-2-one

(c)

H–CH=CH₂ : Ethene

CH₃–CH=CH₂ : Propene

CH₃–CH₂–CH=CH₂ : 1-Butene

CH₃–CH₂–CH₂–CH=CH₂ : 1-Pentene

CH₃–CH₂–CH₂–CH₂–CH=CH₂ : 1-Hexene