Draw the graph of $2 x^{2} - 11 x + 12$ .

Open in App

Solution

$2 x^{2} - 11 x + 12$
$\Rightarrow$ $2 x^{2} - 8 x - 3 x + 12$
$\Rightarrow$ $2 x (x - 4) - 3 (x - 4)$
$\Rightarrow$ $(2 x - 3) (x - 4) = 0$
WE know that $[P]$ is discontinuous at integral value of $P$
ow $sin x + cos x = \sqrt{2} . sin (x + \frac{π}{4})$
$[sin x + cos x] = [\sqrt{2} sin (x + \frac{π}{4})]$ will be discontinuous at integral values of $[\sqrt{2} sin (x + \frac{π}{4})]$ in the interval $(0, 2 π)$
$x = \frac{π}{2}, \frac{3 π}{4}, π, \frac{3 π}{2}, \frac{7 π}{4}$

Suggest Corrections

Similar questions

f (x) = \frac{e^{x} I n x 5^{(} x^{2} + 2) (x^{2} - 7 x + 10)}{2 x^{2} - 11 x + 12}

y = 2 x^{2}

y = 2 x^{2}

2 x^{2} + x - 6 = 0

Draw the graph of $y = 2 x^{2} + 7 x - 9$ .

(1) Draw a graph of y = x² and find the value of.

(2) Draw the graph of y = 2x² and find the value of.

(3) Draw the graph of and find the value of.

Join BYJU'S Learning Program