Question

# Draw the graph of $$2x^2-11x+12$$.

Solution

## $$2{x}^{2}-11x+12$$$$\Rightarrow$$ $$2{x}^{2}-8x-3x+12$$$$\Rightarrow$$ $$2x(x-4)-3(x-4)$$$$\Rightarrow$$ $$(2x-3)(x-4)=0$$WE know that $$[P]$$ is discontinuous at integral value of $$P$$ow $$\sin x+\cos x=\sqrt 2.\sin{(x+\cfrac{\pi}{4})}$$$$[\sin x+\cos x]=[\sqrt{2}\sin{(x+\cfrac{\pi}{4})}]$$ will be discontinuous at integral values of $$[\sqrt {2}\sin {(x+\cfrac{\pi}{4})}]$$ in the interval $$(0,2\pi)$$$$x=\cfrac{\pi}{2},\cfrac{3\pi}{4},\pi,\cfrac{3\pi}{2},\cfrac{7\pi}{4}$$Maths

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