Draw the graph of i) $y = 2 x + 5$ , ii) $y = 2 x - 5$ , iii) $y = 2 x$ and find the point of intersection on $x$ -axis. Is the $x$ -coordinates of these points also the zero of the polynomial ?

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Solution

i)
$y = 2 x + 5$

if $x = 0, y = 5$

if $x = 2, y = 9$

if $y = 5, x = 0$

if $y = 0, x = 2.5$

ii)
$y = 2 x - 5$

if $x = 0, y = - 5$

if $x = 2, y = - 1$

if $x = 3, y = 1$

iii)
$y = 2 x$

if $x = 0, y = 0$

if $x = 1, y = 2$

if $x = 2, y = 4$

if $x = 3, y = 6$

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Draw the graph of i) y=2x+5 , ii) y=2x−5, iii) y=2x and find the point of intersection on x-axis. Is the x-coordinates of these points also the zero of the polynomial ?

i)y=2x+5if x=0,y=5if x=2,y=9if y=5,x=0if y=0,x=2.5ii)y=2x−5if x=0,y=−5if x=2,y=−1if x=3,y=1iii)y=2xif x=0,y=0if x=1,y=2if x=2,y=4if x=3,y=6

Draw the graph of i) $y = 2 x + 5$ , ii) $y = 2 x - 5$ , iii) $y = 2 x$ and find the point of intersection on $x$ -axis. Is the $x$ -coordinates of these points also the zero of the polynomial ?

i)
$y = 2 x + 5$

if $x = 0, y = 5$

if $x = 2, y = 9$

if $y = 5, x = 0$

if $y = 0, x = 2.5$

ii)
$y = 2 x - 5$

if $x = 0, y = - 5$

if $x = 2, y = - 1$

if $x = 3, y = 1$

iii)
$y = 2 x$

if $x = 0, y = 0$

if $x = 1, y = 2$

if $x = 2, y = 4$

if $x = 3, y = 6$