Question

Draw the graph of the equation given below. Also find the coordinates of the points where the graph cuts the coordinate axes:

$3x+2y+6=0$

Answer 1

Given equation:$3x+y+6=0$

$\Rightarrow 2y=-6-3x$

$y=\frac{-6-3x}{2}$

When $x=2\Rightarrow y=\frac{-6-3\left(2\right)}{2}\Rightarrow y=\frac{-12}{2}\Rightarrow y=-6$

When $y=3\Rightarrow 3=\frac{-6-3x}{2}$

$\Rightarrow 6+6=-3x\Rightarrow x=\frac{12}{-3}$

$\Rightarrow x=-4$

Graph:
Mark points $(2,-6)\text{and}(-4,3)$ on the graph and join them

$\therefore$ The graph of the given equation is as follow:




From the graph, we observe the coordinate of the points where the graphs cuts the coordinate axes as $(-2,0)\text{and}(0,-3)$