Draw the graph of y = 3x + 3.
Find the coordinates of the point of interserction of the graph with the axes.

(1, 0) and (0, 3)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(-1, 0) and (0, -3)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(-1, 0) and (0, 3)

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

(1, 0) and (0, -3)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C (-1, 0) and (0, 3)
The given equation y = 3x + 3, means that for any value of x ,
the value of y is three more than thrice of x.

x -1 0 1 2

y 3(-1) + 3 = 0 3(0) + 3 = 3 3(1) + 3 = 6 3(2) + 3 = 9

Plotting the point (−1, 0) (0, 3) (1, 6) (2, 9), we get,Therefore, the coordinates of the point of interserction with the axes are (-1, 0) and (0, 3).

Suggest Corrections

Similar questions

Q. Draw the graph of y = 3x + 3.
Find the coordinates of the point of interserction of the graph with the axes.

If the coordinates of two points A and B are (3,4) and (5,-2) respectively. Then, the coordinates of any point P, if PA = PB and area of $Δ$ PAB = 10, are

Two points A and B have coordinates (1, 0) and (-1, 0) respectively and Q is a point which satisfies the relation

AQ - BQ = $\pm$ 1. The locus of Q is

Q. Find the coordinates of the point equidistant from the points

A (- 2, - 3)

B (- 1, 0)

and

C (7, - 6)

Q. Find the area of the region

{(x, y) : 0 \leq y \leq x^{2} + 1, 0 \leq y \leq x + 1, 0 \leq x \leq 2}

Join BYJU'S Learning Program

Draw the graph of y = 3x + 3. Find the coordinates of the point of interserction of the graph with the axes.

Draw the graph of y = 3x + 3.
Find the coordinates of the point of interserction of the graph with the axes.