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Question

Two points A and B have coordinates (1, 0) and (-1, 0) respectively and Q is a point which satisfies the relation

AQ - BQ = ± 1. The locus of Q is



Solution

The correct option is D


According to the given condition

(x1)2+y2(x+1)2+y2 = ±1

On squaring both sides, we get

2x2+2y2+1=2(x1)2+y2(x+1)2+y2

Again on squaring, we get 12x24y2=3.

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