Question

# Two points A and B have coordinates (1, 0) and (-1, 0) respectively and Q is a point which satisfies the relation AQ - BQ = ± 1. The locus of Q is

Solution

## The correct option is D According to the given condition √(x−1)2+y2−√(x+1)2+y2 = ±1 On squaring both sides, we get 2x2+2y2+1=2√(x−1)2+y2√(x+1)2+y2 Again on squaring, we get 12x2−4y2=3.

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