Two points $A$ and $B$ have coordinates $(1, 0)$ and $(- 1, 0)$ respectively and $Q$ is a point which satisfies the relation $A Q - B Q = \pm 1$ . The locus of $Q$ is

12 x^{2} - 4 y^{2} = 3

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12 x^{2} - 4 y^{2} + 3 = 3

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12 x^{2} + 4 y^{2} = 3

No worries! We‘ve got your back. Try BYJU‘S free classes today!

12 x^{2} + 4 y^{2} + 3 = 3

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Solution

The correct option is A $12 x^{2} - 4 y^{2} = 3$

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Two points A and B have coordinates (1, 0) and (-1, 0) respectively and Q is a point which satisfies the relation

AQ - BQ = $\pm$ 1. The locus of Q is

Q. For the ellipse 12x² + 4y² + 24x − 16y + 25 = 0

(a) centre is (−1, 2)

(b) lengths of the axes are

\sqrt{3}

and 1

(c) eccentricity =

\sqrt{\frac{2}{3}}

(d) all of these

Q. Find the the length of the major axis of ellipse:

12 x^{2} + 4 y^{2} + 24 x - 16 y + 25 = 0

Q. Mark the correct alternative in each of the following:
For the ellipse

12 x^{2} + 4 y^{2} + 24 x - 16 y + 24 = 0

Transforming to parallel axes through a point $(p, q),$ the equation $2 x^{2} + 3 x y + 4 y^{2} + x + 18 y + 25 = 0$ becomes $2 x^{2} + 3 x y + 4 y^{2} = 1.$ Then

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Two points A and B have coordinates (1,0) and (−1,0) respectively and Q is a point which satisfies the relation AQ−BQ=±1. The locus of Q is

The correct option is A 12x2−4y2=3

Two points $A$ and $B$ have coordinates $(1, 0)$ and $(- 1, 0)$ respectively and $Q$ is a point which satisfies the relation $A Q - B Q = \pm 1$ . The locus of $Q$ is

The correct option is A $12 x^{2} - 4 y^{2} = 3$