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B
CH3−CH2−CH2−CH2−CH2Br
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C
Both a and b
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D
None of the above
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Solution
The correct option is ACH3−CH2−CH(Br)−CH2−CH3 Option A is correct. There are numerous possible constitutional isomers of bromopentane. Specifically, the bromine atom can be attached to any of the carbon atoms (although there are only three unique possibilities because the 2 end carbons are identical). So you could have:
1-bromopentane (same molecule as 5-bromopentane, but lower number is used)
2-bromopentane (same molecule as 4-bromopentane, but lower number is used)