Dry slaked lime on reaction with chlorine gives

Pure anhydrous Calcium chloride

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Bleaching powder

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

A combination of

C a (O C l)_{2}

, dibasic Calcium hypochlorite -

C a_{3} (O C l)_{2} (O H)_{4}

and dibasic Calcium Chloride -

C a_{3} C l_{2} (O H)_{4}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Both (A) and (C)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C A combination of $C a (O C l)_{2}$ , dibasic Calcium hypochlorite - $C a_{3} (O C l)_{2} (O H)_{4}$ and dibasic Calcium Chloride - $C a_{3} C l_{2} (O H)_{4}$ .
$2 C a (O H)_{2} + 2 C l_{2} \to C a (O C l)_{2} + C a C l_{2} + 2 H_{2} O$
Dry slaked lime on reaction with chlorine gives Calcium oxychloride also called Bleaching Powder. Do note that $C a (O C l)_{2}$ is also called Calcium Hypochlorite.

$N a O C l$ - Sodium hypochlorite, is called liquid bleach. In general, bleaching powder is more stable than $N a O C l$ and also has more available Chlorine. Do note that the term "bleaching powder" is a blanket term. It is not just a simple combination of Calcium hypochlorite $C a (O C l)_{2}$ , Calcium chloride $C a C l_{2}$ and Calcium Hydroxide $C a (O H)_{2}$ . Instead, it consists of $C a (O C l)_{2}$ mainly, dibasic Calcium hypochlorite, $C a_{3} (O C l)_{2} (O H)_{4}$ and dibasic Calcium Chloride, $C a_{3} C l_{2} (O H)_{4}$ .

Suggest Corrections