Question

Dual of $(x+y).(x+1)=x+x.y+y$ is

• A. $(x.y)+\left(x.0\right)=x.(x+y).y$
• B. $(x.y)+\left(x.1\right)=x.(x+y).y$
• C. $(x.y)\left(x.0\right)=x.(x+y).y$
• D. None of these

Answer 1

Answer: (A)

$(x.y)+\left(x.0\right)=x.(x+y).y$

Given $(x+y).(x+1)=x+x.y+y$

to find dual of the given expression, we need to replace Ands i.e. '$.$' by

Or i.e. '$+$'

Or ('+') by Ands ('$.$'), $1$ by $0$ and we get

Dual of $(x+y).(x+1)=x+x.y+y$ is

$(x.y)+\left(x.0\right)=x.(x+y).y$

Hence, option A is correct.