Dual to $x . (y + x) = x$ is

x + (y . x) = x

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x . (y . x) = x

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(x + y) . (x + x) = x

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None of the above

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Solution

The correct option is A $x + (y . x) = x$
$x . (y + x) = x$
Its dual is $x + (y . x) = x$

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Similar questions

(x + y) . (x + 1) = x + x . y + y

[\begin{matrix} < x . x > & < x . y > < y . x > & < y . y > \end{matrix}]

Solve for x and y.

x+y=a+b

ax-by=a^2-b^2

Solve by substitution and elimination method.

X

Y . X

Y

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