During a medical check-up, the number of heartbeats per minute of 30 patients were recorded and summarised as follows:
Number of heart-beats per minute.65−6868−7171−7474−7777−8080−8383−86Number of patients2438742 Find the mean heartbeats per minute for these patients, choosing a suitable method.
Using Direct method, the given data is shown as follows:
Number of heartbeats per minute | Number of patients (fi) | Class mark (xi) | (fixi) |
65 - 68 | 2 | 66.5 | 133 |
68 - 71 | 4 | 69.5 | 278 |
71 - 74 | 3 | 72.5 | 217.5 |
74 - 77 | 8 | 75.5 | 604 |
77 - 80 | 7 | 78.5 | 549.5 |
80 - 83 | 4 | 81.5 | 326 |
83 - 86 | 2 | 84.5 | 169 |
Total | ∑fi=30 | ∑(fi×xi)=2277 |
The mean of given data is given by
¯x = ∑(fi×xi)/∑fi
= 2277/30
= 75.9
Thus, the mean heartbeats per minute for these patients are 75.9.