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During a ther...

Question

During a thermodynamic process, the product of PV increases by $40$ L atm and the change in internal energy is $200$ J. Calculate the value of $Δ H$ for the process.

A

240

J

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B

3.8 k J

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C

4.2

kJ

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D

160

J

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Solution

The correct option is C $4.2$ kJ
Given, $△ U = 200 J$
$P △ V = 40 L a t m$
$1 L a t m = 101.33 J$
$P △ V = 40 \times 101.33 J$
$P △ V = 4053.2 J$
Using the reaction,
$△ H = △ U + P △ V$
$= 200 J + 4053.2 J$
$△ H = 4253.2 J$

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