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Question

During acetylation of glucose it needs x moles of acetic anhydride. The value of x would be:

A
3
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B
5
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C
4
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D
1
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Solution

The correct option is A 5
Acetylation of glucose with acetic anhydride gives glucose pentaacetate which confirms the presence of five OH groups.
Glucose+5H3CO||COO||CCH3Acetylation−−−−−−CHO(CHOO||CCH3)4(CH2OO||CCH3)

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