Question

During an experiment, a signal from a spaceship reached the ground state in 5 minutes. What was the distance of the spaceship from the ground state if signal travels at the speed of light, that is $3\times {10}^{8}m{s}^{-1}$

Answer 1

Given that,

Speed of signal $u=3\times {10}^{8}m/s$

Now, time taken

$t=5min$

$t=5\times 60$

$t=300s$

We know that,

$V=\frac{D}{t}$

$D=v\times t$

$D=3\times {10}^8\times 300$

$D=9\times {10}^{10}m$

Hence, the distance of the spaceship from the ground state is $9\times {10}^{10}m$