During the formation of a chemical bond:

electron-electron repulsion becomes more than the nucleus-electron attraction

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energy of the system does not change

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energy increases

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energy decreases

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Solution

The correct option is D energy decreases
When a bond forms, electrons are attracted to the space between nuclei where the electrostatic force of attraction is greater. As the electrons fall to a position of lower potential energy, the total mechanical energy of the molecular system decreases.

Hence, option D is correct.

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1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 3 d^{2} 4 s^{2}

, the four electrons involved in chemical bond formation will be:

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Question 12

If the electronic configuration of an element is $1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 3 d^{2} 4 s^{2}$ the four electrons involved in chemical bond formation will be

(a) $3 p^{6}$

(b) $3 p^{6}, 4 s^{2}$

(d) $3 d^{2}, 4 s^{2}$

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