The correct option is B Zn(s)|Zn2+(1M)||Ag+(1M))|Ag(s)
E0cell=E0cathode−E0anode
More postive the value of E0cell, △G0 will be more negative.
△G0=−nFE0cell
For option A, E0cell=−1.61
For option B, E0cell=1.56
For option C, E0cell=0.46
For option D, E0cell=−1.98
ΔG∘ is the most negative for (B).