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Question

The EMFs of the following cells are
Cu|Cu2+(1M)||Ag+(1M)|Ag,Eo=0.46V
Zn|Zn2+(1M)||Cu2+(1M)|Cu,Eo=1.10V
The EMF of the cell
Zn|Zn2+||Ag+(1M)|Ag will be:

A
1.56V
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B
1.56V
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C
0.64V
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D
2.02V
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Solution

The correct option is A 1.56V
According to the question:
Cu|Cu2+(1M)||Ag+(1M)|Ag,Eo=0.46V.....(1)
Zn|Zn2+(1M)||Cu2+(1M)|Cu,Eo=1.10V.....(2)
Zn|Zn2+||Ag+(1M)|Ag.....(3)
From cell (1),[Cu+2Ag+(1M)Cu2+(1M)+2Ag]E1o=0.46V
From cell (2),[Zn+Cu2+(1M)Zn2+(1M)+Cu]E2o=1.10V
After adding (1) and (2), we get (3)
[Cu+2Ag+(1M)Cu2+(1M)+2Ag]+[Zn+Cu2+(1M)Zn2+(1M)+Cu]–––––––––––––––––––––––––––––––––––––––––––Zn+2Ag+(1M)Zn2+(1M)+2Ag––––––––––––––––––––––––––––––––––––––––
Enet=E1o+E2o=0.46V+1.10V=1.56V
The correct option is (A)

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