$E_{C u^{2 +} | C u}^{0} = + 0.337 V, E_{Z n^{2 +} | Z n}^{0} = - 0.762 V$ .

The EMF of the cell, $Z n | Z n^{2 +} (0.1 M) | | C u^{2 +} (0.01 M) | C u$ is:

+1.099 V

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- 1.099 V

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+ 1.069 V

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-1.069 V

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Solution

The correct option is C + 1.069 V

Oxidation: $Z n \to Z n^{+ 2} + 2 e^{-}$

Reduction: $C u^{+ 2} + 2 e^{-} \to C u$

Therefore overall reaction is:
$Z n + C u^{+ 2} \to Z n^{+ 2} + C u$

$E_{c e l l}^{0} = E_{c u^{+ 2} / c u}^{0} - E_{Z n^{+ 2} / Z n}^{0}$

$E_{c e l l}^{0} = + 0.337 - (- 0.762)$ volts

$= 1.099$ Volts

$E_{c e l l} = E_{c e l l}^{0} - \frac{0.0592}{2} l o g \frac{[Z n^{2 +}]}{[C u^{2 +}]}$

= $1.099 - 0.0296$

= $1.069 V$

Option C is correct

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Similar questions

Z n | Z n^{2 +} (0.001 M) | | C u^{2 +} (0.1 M) | C u

C u / C u^{2 +}

Z n / Z n^{2 +}

E M F

Z n | Z n^{2 +} (0.01 M) | | C u^{2 +}] (0.1 M) | C u

298 K

Z n | Z n^{2 +} (a q) (1.0 M) | | C u^{2 +} (a q) (1.0 M) | | C u

C u^{2 +} (a q) + 2 e^{-} \to C u

Z n^{2 +} (a q) + 2 e^{-} \to Z n

Z n / Z n^{2 +} (a = 0.1) / / C u^{2 +} (a = 0.01) / C u

E_{Z n^{2 +}}^{o} / Z n = - 0.762 V

E_{C u^{2 +}}^{o} / C u = + 0.337 V

emf of the following cell at 298 $K$ in $V$ is $x$ $\times 10^{- 2}$

$Z n (s) | Z n^{2 +} (0.1 M) | | A g^{+} (0.01 M) | A g (s)$

The value of $x$ is____. (Rounded off to the nearest integer)

Given: $E_{Z n^{2 +} / Z n}^{0} = - 0.76 V; E_{A g^{+} / A g}^{0} = + 0.80 V; \frac{2.303 R T}{F} = 0.059$

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