Question

$E_n=-313.6/n^{2}kcal/mole$. If the value of $E=-34.84kcal/mole$, to which value does $n$ correspond?

• A. $4$
• B. $3$
• C. $2$
• D. $1$

Answer 1

The correct option is B $3$

Given that $-313.6/n^2=-34.84$ so we have $n^2=\frac{313.6}{34.84}$

or $n=3$

Option B is correct.