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Question

EoRP and their respective half reactions for some changes are given below:

(a) MnO4(aq)+8H++5eMn2+(aq)+4H2O(l); Eo=+1.52V
(b) MnO24(aq)+4H++2eMnO2(s)+2H2O(l); Eo=+2.26V
(c) 2MnO4(aq)+2e2MnO24(aq); Eo=+0.56V (acid med.)
(d) Mn3++eMn2+; Eo=+1.51V (acid med.)
(e) Mn4++eMn3+; Eo=0.95V (acid med.)

The most stable oxidation state of Mn is :

A
Mn2+
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B
Mn4+
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C
Mn7+
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D
Mn6+
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Solution

The correct option is A Mn2+
From the above chemical series, Mn2+ is a more stable oxidation state than Mn. Because in Mn2+ no. of d electrons are 5, which is half-filled but Mn is partially filled. Half filled electronic configuration is more stable than partially filled.

This can also be observed from the reduction potential Mn from different oxidation state to Mn2+ where all the reduction potentials are positive.

So, the correct option is A

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