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Question

Standard electrode potential data are useful for understanding the suitability of an oxidant in a redox titrations. Some half cell reactions and their standard potentials are given below:
MnO4(aq.)+8H+(aq.)+5eMn2+(aq.)+4H2O(l);Eo=1.51V
Cr2O27(aq.)+14H+(aq.)+6e2Cr3+(aq.)+7H2O(l);Eo=1.38V
Fe3+(aq.)+eFe2+(aq.);Eo=0.77V
Cl2(g)+2e2Cl(aq.);Eo=1.40V
Identify the only incorrect statement regarding the quantitative estimation of aqueous Fe(NO3)2.

A
MnO4 can be used in aqueous HCl.
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B
CrO27 can be used in aqueous HCl.
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C
MnO4 can be used in aqueous H2SO4.
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D
CrO27 can be used in aqueous H2SO4.
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Solution

The correct option is A MnO4 can be used in aqueous HCl.
MnO4 will oxidise Cl ion according to equation,

Mn7++5eMn2+
2ClCl2+2e
Thus, Eocell=EoOPCl/Cl2+EoRPMnO4/Mn2+
=1.40+1.51=0.11V
or reaction is feasible MnO4 will oxidise Fe2+ to Fe3+
Mn7++5eMn2+
Fe2+Fe3++e
Eocell=EoOPFe2+/Fe3++EMnO4/Mn2+
=0.77+1.51
=0.74V or reaction is feasible
Thus, MnO4 will not only oxidise Fe2+ to Fe3+ in aqueous HCl medium but it will also oxidise Cl to Cl2. Suitable oxidant should not oxidise Cl to Cl2 and should only oxidise fe2+ to Fe3+ in redox titrations.
So MnO4 can not be used in aqueous HCl.

Hence,option A is correct.

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