MnO−4 will oxidize Cl− into Cl2 according to the following equation:
2 MnO−4+16 H+10 Cl−→2Mn2++8 H2O+5 Cl2
The corresponding cell is
PtCl2(1 atm) |Cl−| |MnO−4,Mn2+,H+ |Pt
A positvie value confirms that the above process is spontaneous. Thus, MnO−4 will oxidize Cl− as well as Fe(NO3)2 simultaneously.