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Question

Standard electrode potential data are useful for understanding the suitability of an oxidant in a redox Titration. Some half – cell reactions and their standard potential are given below:
MnO4(aq)+8H+(aq)+5eMn2+(aq)+4H2O(I); E=1.51 V
Cr2 O27 (aq)+14H+(aq)+6e2Cr3+(aq)+7H2O(I); E=1.38V
Fe3+(aq)+eFe2+(aq); E=0.77V
Cl2(g)+2e2Cl(aq); E=1.40V

Identify the only incorrect statement regarding the quantitative estimation of aqueous Fe(NO3)2.


A

MnO4 can be used in aqueous HCl

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B

Cr2O27 can be used in aqueous HCl

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C

MnO4 can be used in aqueous H2SO4

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D

Cr2O27 can be used in aqueous H2SO4

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Solution

The correct option is A

MnO4 can be used in aqueous HCl


MnO4 will oxidize Cl into Cl2 according to the following equation:
2 MnO4+16 H+10 Cl2Mn2++8 H2O+5 Cl2
The corresponding cell is
PtCl2(1 atm) |Cl| |MnO4,Mn2+,H+ |Pt
Ecell=+1.511.40=+0.11 V
A positvie value confirms that the above process is spontaneous. Thus, MnO4 will oxidize Cl as well as Fe(NO3)2 simultaneously.


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