Question

E represents an element belonging to carbon family. $E+2X_2\to E{X}_4(X=F,Cl,Br,I)$

• A. Stability of $E{X}_4$ decreases down the ${14}^{th}$ group
• B. $Pb{I}_4$ does not exist
• C. Ge and Pb form $E{X}_2$ as well
• D. All are correct

Answer 1

The correct option is D

All are correct

Stability of $E{X}_4$ decreases down the ${14}^{th}$ group because of the inert pair effect. Lead (IV) iodide is not known yet probably because of the oxidizing nature of $P{b}^{4+}$ and the reducing nature of $I^{-}$. Ge and Pb definitely form $E{X}_2$.