Question

Each . in the mileage table above represents an entry indicating the distance between a pair of the five cities. If the table were extended to represent the distances between all pairs of 30 cities and each distance were to be represented by only one entry,how many entries would the table then have?

• A. 60
• B. 435
• C. 450
• D. 465
• E. 900

Answer 1

Answer: (B)

435

City B, the second city has 3 points

City C the third city has 2 points

City D, the fourth city has 1 point.

What's the pattern?

(Number of the city) - 1 .

So, the 30th city is going to have 29 points.

Then it becomes a matter of adding the consecutive integers from 1 to 29

Average = 15

Number of terms = 29

29*15 = 435 (option B)