Question 88

Each of the 2 equal sides of an isosceles triangle is twice as large as the third side. If the perimeter of the triangle is 30 cm, find the length of each side of the triangle.

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Solution

Let the third side of an isosceles triangle be x. Then, two other equal sides are twice.
So, length of equal sides are 2x and 2x.
We know that perimeter of a triangle is equal to the sum of all sides of the triangle.
According to the question,
$x + 2 x + 2 x = 30 \Rightarrow 5 x = 30$
On dividing both sides by 5, we get
$\frac{5 x}{5} = \frac{30}{5} \Rightarrow x = 6 c m$
$∴$ Third side = x = 6 cm
So, the other equal sides are 2x $= 2 \times 6 = 12 c m$ and $2 x = 2 \times 6 = 12 c m .$

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Applications (Word Problem)

Standard VII Mathematics

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Question 88 Each of the 2 equal sides of an isosceles triangle is twice as large as the third side. If the perimeter of the triangle is 30 cm, find the length of each side of the triangle.

Question 88

Each of the 2 equal sides of an isosceles triangle is twice as large as the third side. If the perimeter of the triangle is 30 cm, find the length of each side of the triangle.