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Question

Each of the plates shown in the figure has surface area (96/ϵ0)×1012 Fm on one side and the separation between the consecutive plates is 4.0mm. The emf of the battery connected is 10 volts. Find the magnitude of the charge supplied by the battery to each of the plates connected to it.
1060047_65975eec7ea3441396f221eca43cef36.png

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Solution

Here three capacitors are formed
And each of
Surface area of the plates is A=96ε0×1012f.m
The distance between the plates is d=4mm=4×103m

Capacitance of a capacitor
C=ε0Ad=ε096×1012ε04×103=24×109F

As three capacitor are arranged is series
So, Ceq=Cq=24×1093=8×109

The total charge to a capacitor
q=CV
=8×109×10=8×108C

The charge of a single Plate q=2×8×108=16×108=0.16×106=0.16μC

1545051_1060047_ans_857d09746637470e8ab61bb513fe042f.JPG

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