Question

Each of the two equal sides of an isosceles right triangle is $10cm$ long. Its area is.

• A. $10\sqrt{3}c{m}^2$
• B. $50c{m}^2$
• C. $5\sqrt{10}c{m}^2$
• D. $75c{m}^2$

Answer 1

The correct option is B

$50c{m}^2$

Explanation for the correct option:

Find the area of the triangle

Since it is given that triangle is an isosceles right-angled triangle so,

$$\begin{gathered} base=10cm \\ height=10cm \end{gathered}$$

It is known that the area of the triangle can be given as: $\frac{1}{2}\times base\times height$.

So, the area of the triangle will be,

$$\begin{gathered} A=\frac{1}{2}\times 10\times 10 \\ \Rightarrow A=50c{m}^2 \end{gathered}$$

Hence, the correct option is (b) $50c{m}^2$.