Question

Each of the two equal sides of an isosceles triangle is 1 cm less than the third. If its perimeter is 16 cm, find the sides of the triangle.

Answer 1

R,E.F image

Let the third side, Bc be x cm

Then, the other sides = (x - 1),(x - 1) cm each

$\therefore$ Perimeter = 16

$\therefore (x-1)+(x-1)+x=16$

3x - 2 = 16

3x = 18

x = 6 cm

AB = AC = 5cm , BC = 6 cm