Each square on the Rubik's cube has a side length of 1 unit. Find the sum of the area of all the faces of the cube.

55 square units

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54 square units

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53 square units

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52 square units

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Solution

The correct option is B 54 square units
A cube has 6 square faces.
Each face of the cube has 9 squares.

Area of 1 face = 9 square units

Area of 6 faces = $9 \times 6$
= 54 square units

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Each square on the Rubik's cube has a side length of 1 unit. Find the sum of the area of all the faces of the cube.

The correct option is B 54 square unitsA cube has 6 square faces. Each face of the cube has 9 squares. Area of 1 face = 9 square units Area of 6 faces = 9×6 = 54 square units

The correct option is B 54 square units
A cube has 6 square faces.
Each face of the cube has 9 squares.

Area of 1 face = 9 square units

Area of 6 faces = $9 \times 6$
= 54 square units