Earth completes one revolution around the sun in 365 days- Calculate its angular velocity in rad-s- If the average distance from the sun is 150 million km- find Earth-s linear velocity- -3 MARKS-

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Standard IX

Physics

Third Equation of Motion

Earth complet...

Question

Earth completes one revolution around the sun in 365 days. Calculate its angular velocity in $\frac{r a d}{s}$ . If the average distance from the sun is 150 million km, find Earth's linear velocity. [3 MARKS]

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Solution

Finding angular velocity : 2 Marks
Finding linear velocity : 1 Mark

Time period, $T = 365 d a y s$
= $365 \times 24 \times 60 \times 60 s$
= $31536000 s$

$A n g u l a r v e l o c i t y ω = \frac{2 π}{T} = \frac{2 π}{31536000} = 1.99 \times 10^{- 7} \frac{r a d}{s}$
$L i n e a r v e l o c i t y v = r ω = 1.99 \times 10^{- 7} \frac{r a d}{s} \times 150, 000, 000$ = $30 k m / s$

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Earth completes one revolution around the sun in 365 days. Calculate its angular velocity in rads. If the average distance from the sun is 150 million km, find Earth's linear velocity. [3 MARKS]

Finding angular velocity : 2 Marks Finding linear velocity : 1 Mark Time period, T=365 days = 365×24×60×60s = 31536000 s Angular velocity ω=2πT=2π31536000=1.99×10−7rads Linear velocity v=rω=1.99×10−7rads×150,000,000 = 30 km/s

Earth completes one revolution around the sun in 365 days. Calculate its angular velocity in $\frac{r a d}{s}$ . If the average distance from the sun is 150 million km, find Earth's linear velocity. [3 MARKS]