Effective atomic number of $F e$ in $F e_{2} {(C O)}_{9}$ is:

35

No worries! We‘ve got your back. Try BYJU‘S free classes today!

36

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

37

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Cannot be calculated

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $36$
$E A N$ = $Atomic number of the central metal + 3 \times 2 (3 terminal ligands attached to each$
$central atom which donate 2 electrons) + 3 \times 1 (3 bridging ligands which donate 1$
$electron each) + 1 (1 Fe-Fe bond)$

$= 26 + 6 + 3 + 1$

$= 36$

Suggest Corrections

Similar questions

F e

F e_{2} {(C O)}_{9}

[F e (H_{2} O)_{5} N O]^{2 +}

The effective atomic number of iron in $[F e (C N)_{6}]^{3 -}$ is ?

F e_{2} (C O)_{9}

K_{4} F e (C N)_{6}

C r (C O)_{6}

F e (Z = 26)

C r (Z = 24)

Join BYJU'S Learning Program