Electric charges -q, -q, -q and 3q are placed at the corners of a square ABCD of length/as shown in figure. The magnitude of electric dipole moment of the system is

\sqrt{2} q l

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2ql

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\sqrt{2} q l

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $\sqrt{2} q l$
The distance $= \sqrt{l^{2} + l^{2}} = \sqrt{{2 l}^{2}} = l \sqrt{2}$
The electric dipole $= q \times l \sqrt{2} = \sqrt{2} q l$

Suggest Corrections

Similar questions

Electric charges q, -q, -q and 3q are placed at the comers of a square ABCD of length I was shown in the figure. The magnitude of the electric dipole moment of the system is

Q. Electric charges

q, q

and

- 2 q

are placed at the corners of an equilateral triangle ABC of side

L

. The magnitude of electric dipole moment of the system is

Q. Electric charge Q, Q and -2Q respectively are placed at the three corners of an equilateral triangle of side a. Magnitude of the electric dipole moment of the system is

Q. Electric charge

q

q

and

- 2 q

are placed at the corners of an equilateral triangle

A B C

of side

L

. The magnitude of electric dipole moment of the system is

Q. Point charges q, q, -2q are placed at the corners of an equilateral triangle ABC of side l. The magnitude of net electric dipole moment of the system is

Join BYJU'S Learning Program

Electric charges -q, -q, -q and 3q are placed at the corners of a square ABCD of length/as shown in figure. The magnitude of electric dipole moment of the system is

The correct option is A √2qlThe distance =√l2+l2=√2l2=l√2The electric dipole =q×l√2=√2ql

The correct option is A $\sqrt{2} q l$
The distance $= \sqrt{l^{2} + l^{2}} = \sqrt{{2 l}^{2}} = l \sqrt{2}$
The electric dipole $= q \times l \sqrt{2} = \sqrt{2} q l$