Question

Electric ield on the axis of small electric dipole at a distance r is $\overrightarrow{E_1}$ and $\overrightarrow{E_2}$ at a distance $2$r on a line of perpendicular dissector. Then

• A. $\overrightarrow{E_2}=-\frac{\overrightarrow{E_1}}{8}$
• B. $\overrightarrow{E_2}=-\frac{\overrightarrow{E_1}}{16}$
• C. $\overrightarrow{E_2}=-\frac{\overrightarrow{E_1}}{4}$
• D. $\overrightarrow{E_2}=\frac{\overrightarrow{E_1}}{8}$

Answer 1

The correct option is A $\overrightarrow{E_2}=-\frac{\overrightarrow{E_1}}{8}$

Electric field on the axis of small electric diapole at a distance r

$\overrightarrow{E_1}$ and$\overrightarrow{E_2}$ at a distance

$=2r$

On a line of perpendicular dissector

Then,

Solution

$E_{axis}=\frac{2KP}{r^2}\left(along\overrightarrow{P}\right)E=\frac{1}{4\pi E_0}\frac{2Pr}{(r^2-l^2{)}^2}=\frac{1}{4\pi E_0}\frac{2Pr}{r^4}=-\frac{E_{axis}}{8}$