The electric field due to an electric dipole at a distance $r$ from its center on the axial line is $E$ . If the dipole is rotated through an angle of $90^{\circ}$ about its perpendicular axis, electric field at the same point will be

\frac{E}{2}

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E

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2 E

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\frac{E}{4}

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Solution

The correct option is A $\frac{E}{2}$

Given, $|_{a x} | = E$

$|_{a x} | = \frac{2 k p}{r^{3}} and$

$|_{e q u} | = \frac{k p}{r^{3}}$

After $90^{\circ}$ rotation, the point lies on the equatorial line of the dipole.

$∴ E_{e q} = \frac{E_{a x}}{2} = \frac{E}{2}$

 Hence, (a) is the correct answer.

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The electric field due to an electric dipole at a distance r from its center on the axial line is E. If the dipole is rotated through an angle of 90∘ about its perpendicular axis, electric field at the same point will be

The correct option is A E2 Given, |−−→Eax|=E |−−→Eax|=2kpr3 and |−−→Eequ|=kpr3 After 90∘ rotation, the point lies on the equatorial line of the dipole. ∴ Eeq=Eax2=E2  Hence, (a) is the correct answer.

The electric field due to an electric dipole at a distance $r$ from its center on the axial line is $E$ . If the dipole is rotated through an angle of $90^{\circ}$ about its perpendicular axis, electric field at the same point will be