Question

Electrochemical equivalents of $Mg$ and $Al$ have been given. Find the correct alternative for their values from given below.
$\left(a\right)1.24\times {10}^{-4}g/C$ $\left(b\right)93.26\times {10}^{4}g/C$
$\left(c\right)12.4\times {10}^{-4}g/C$ $\left(d\right)9.326\times {10}^{-5}g/C$
$\left(e\right)2.48\times {10}^{-5}g/C$

• A. $a$ and $b$
• B. $b$ and $c$
• C. $a$ and $d$
• D. $d$ and $e$

Answer 1

Answer: (C)

$a$ and $d$

Electrochemical equivalents = $\frac{EquivalentWeight}{Farada{y}^{\prime }sconstant}$
Thus for $Mg$ = $\frac{24.312/2}{96500}$ =$1.24\times {10}^{-4}$ $g/C$
for $Al$ = $\frac{26.9185/3}{96500}$ =$9.326\times {10}^{-5}$ $g/C$