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Question

Electrolysis of dil. H2SO4 liberates gases at anode and cathode respectively

A
O2,SO3
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B
O2,SO2
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C
O2,H2
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D
H2,SO2
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Solution

The correct option is C O2,H2
in electrolysis of dil. H2SO4 we have,
at cathode: 2H++2eH2
at anode: 4OH2H2O+O2+4e
because OH is having lower reduction potential than SO24.
so, oxidation of OH ion takes palce.


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