Electrolyte KCl KNO3 HCl NaOAc NaCl S cm 2 mol -1 - 149-9 145-0 426-2 91-0 126-5Calculate - HOAc using appropriate molar conductances of the electrolytes listed above at infinite dilution in H2O at 25oC-

The correct option is A 390.7 .Using the given data, Λ #160;^∞ #160;_ HOAc =Λ #160;^∞ #160;_ NaOAC +Λ #160;^∞ #160;_ HCl Λ #160;^∞ #1 ...

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Byju's Answer

Standard XII

Chemistry

Types of Redox Reactions

Electrolyte ...

Question

Electrolyte $K C l$ $K {N O}_{3}$ $H C l$ $N a O A c$
$N a C l$
$Λ^{\infty} (S {c m}^{2} {m o l}^{- 1})$ $149.9$ $145.0$
$426.2$ $91.0$ $126.5$

Calculate ${Λ^{\infty}}_{H O A c}$ using appropriate molar conductances of the electrolytes listed above at infinite dilution in $H_{2} O$ at $25^{o} C$ .

517.2

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552.7

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390.7

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217.5

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Solution

The correct option is A $390.7$ .
Using the given data,

${Λ^{\infty}}_{H O A c} = {Λ^{\infty}}_{N a O A C} + {Λ^{\infty}}_{H C l} - {Λ^{\infty}}_{N a C l}$

$= 91.0 + 426.2 - 126.5$ ${c m}^{2} {m o l}^{- 1}$

$= 390.7 S$ ${c m}^{2}$ ${m o l}^{- 1}$

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Similar questions

Electrolyte $\land^{\infty} (S c m^{2} m o l^{- 1})$

$K C l$ 149.9

$K N O_{3}$ 145.0

$H C l$ 426.2

$N a O A c$ 91.0

$N a C l$ 126.5

Calculate $Λ {^{\infty}}_{H O A c}$ using appropriate molar conductances of the electrolytes listed above at infinite dilution with $H_{2} O$ at 25 $^{o}$ C?

Q. Calculate

Λ_{H N O_{3}}^{0}

and

Λ_{H O A c}^{0}

using appropriate molar conductances of the electrolytes listed below at infinite dilution in

H_{2} O

25^{\circ} C

Electrolyte	$Λ^{0} (S c m^{2} m o l^{- 1})$
$K C l$	$149.9$
$N a C l$	$126.5$
$H C l$	$426.2$
$K N O_{3}$	$145.0$
$N a O A c$	$91.0$

Electrolyte	$K C l$	$K N O_{3}$	$H C l$	$N a O A c$	$N a C l$
$Λ^{\infty} {(Scm}^{2} {mol}^{- 1})$	$149.9$	$145$	$426.2$	$91$	$126.5$

Calculate

Λ_{H O A c}^{\infty}

using appropirate molar conductances of the electrolytes listed above at infinite dilution in

H_{2} O

25^{o} C

Electrolyte $\land^{\infty} (S c m^{2} m o l^{- 1})$

KCl 149.9

KNO $_{3}$ 145.0

HCl 426.2

NaOAc 91.0

NaCl 126.5

Calculate $\land {^{\infty}}_{H O A c}$ using appropriate molar conductances of the electrolytes listed above at infinite dilution in $H_{2} O$ at 25 $^{0}$ C:

Q. Calculate

Δ_{H O A c}^{\infty}

(i n S c m^{2} m o l^{- 1})

using appropriate molar conductances of the electrolytes listed in the given table at infinite dilution in

H_{2} O

25^{0}

Electrolyte	KCl	KNO $_{3}$	HCl	NaOAc	NaCl
$Δ^{\infty} (S c m^{2} m o l^{- 1}$	149.9	145.0	426.2	91.0	126.5

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Electrolyte	$K C l$	$K {N O}_{3}$	$H C l$	$N a O A c$	$N a C l$
$Λ^{\infty} (S {c m}^{2} {m o l}^{- 1})$	$149.9$	$145.0$	$426.2$	$91.0$	$126.5$

ElectrolyteKClKNO3HClNaOAcNaClΛ∞(Scm2mol−1)149.9145.0426.291.0126.5Calculate Λ∞HOAc using appropriate molar conductances of the electrolytes listed above at infinite dilution in H2O at 25oC.

The correct option is A 390.7.Using the given data,Λ∞HOAc=Λ∞NaOAC+Λ∞HCl−Λ∞NaCl =91.0+426.2−126.5 cm2mol−1 =390.7 S cm2 mol−1

The correct option is A $390.7$ .
Using the given data,

${Λ^{\infty}}_{H O A c} = {Λ^{\infty}}_{N a O A C} + {Λ^{\infty}}_{H C l} - {Λ^{\infty}}_{N a C l}$

$= 91.0 + 426.2 - 126.5$ ${c m}^{2} {m o l}^{- 1}$

$= 390.7 S$ ${c m}^{2}$ ${m o l}^{- 1}$