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Question

Electrolyte (Scm2mol1)

KCl 149.9

KNO3 145.0

HCl 426.2

NaOAc 91.0

NaCl 126.5

Calculate HOAc using appropriate molar conductances of the electrolytes listed above at infinite dilution in H2O at 250C:


A
217. 5
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B
390.7
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C
552.7
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D
517.2
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Solution

The correct option is B 390.7
According to Kohlrausch law of independent migration of ions, the molar conductivity of an electrolyte at infinite dilution is equal to the sum of the contributions of the molar conductivities of its ions.
Hence,
ΛHOAc=ΛH++ΛAcO

=ΛNaOAc+ΛHClΛNaCl

Substitute the values in the above equation:

ΛHOAc=91.0+426.2126.5=390.7Ω1cm2mol1.

Option B is correct.

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