Electronic configuration of deuterium atom is

1 s^{1}

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2 s^{2}

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2 s^{1}

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1 s^{2}

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Solution

The correct option is A $1 s^{1}$

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Similar questions

{1 s}^{2} {2 s}^{2} {2 p}^{3}

{1 s}^{2} {2 s}^{2} {2 p x}^{1} {2 p y}^{1} {2 p z}^{1}

The element whose electronic configuration is $1 s^{2}, 2 s^{2}, 2 p^{6}, 3 s^{2}$ is a/an?

\begin{matrix} List-I & List - II P. & 1 s^{2} & 1. & Element shows highest negative oxidation state Q. & 1 s^{2} 2 s^{2} 2 p^{5} & 2. & Element shows highest first ionisation enthalpy R. & 1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{5} & 3. & Element shows highest electronegativity on Pauling scale S. & 1 s^{2} 2 s^{2} 2 p^{2} & 4. & Element shows maximum electron gain enthalpy (most exothermic) \end{matrix}

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