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Byju's Answer
Standard XII
Chemistry
Shapes of Orbitals and Nodes
Electronic co...
Question
Electronic configuration of
H
−
is:
A
1
s
0
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B
1
s
1
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C
1
s
2
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D
1
s
1
2
s
1
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Solution
The correct option is
C
1
s
2
Suggest Corrections
0
Similar questions
Q.
The electronic configuration is
1
s
1
for __________.
Q.
Helium can be excited to the
1
s
1
2
p
1
configuration by light of
58.44
n
m
. The lowest excited singlet state, with the configuration
1
s
1
,
2
s
1
lies
4857
c
−
1
below
1
s
1
2
p
1
state. What would be the average
H
e
−
H
bond energy (
k
J
m
o
l
−
1
) have to be in order that
H
e
H
2
could form non-endothermically from
H
e
and
H
2
? Assume that the compound would form from the lowest excited singlet state of helium. Neglect any differences between
Δ
U
and
Δ
H
. Take
Δ
h
f
(
H
)
=
218.0
K
j
/
m
o
l
.
Q.
1
s
2
is not the electronic configuration of:
Q.
The correct set of values of
n
,
l
,
m
l
and
m
s
for the singly occupied
1
s
1
orbital is:
Q.
The electronic configuration
1
s
2
2
s
2
2
p
x
1
2
p
y
1
2
p
z
1
is of:
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