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Question

Electrons are emitted with zero velocity from a metal surface, when it is exposed to a radiation of wavelength 6800 Å . Then work function of metal is

A

2.92 X 10-19 ergs

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B

2.92 X 10-19 J

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C

2.92 X 10-19 eV

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D

2.92 X 10-19 Cal

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Solution

The correct option is D 2.92 X 10-19 JWavelength of radiation is =6800×10−10m Now threshold frequency vo=cλvo=3×108ms−16800×10−10m=4.41×1014s−1(work function) = w = hv0= 6.626×10−34Js×4.41×1014s−1Workfunction=2.92×10−19J = hcλ0 = 6.625 × 10−34 × 3 × 1086.8 10−10 × 103 = 3 × 6.625 × 10−196.8 = 2.92 × 10−19 J

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