Element 'B ' forms ccpstructure and 'A ' occupies half of the octahedral voids, while oxygen atoms occupy all the tetrahedral voids. The structure of bimetallic oxide is:

A_{4} B O_{4}

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A B_{2} O_{4}

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A_{2} B_{2} O

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A_{4} B_{2} O

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Solution

The correct option is B $A B_{2} O_{4}$
The number of element ' B ' in the crystal structure $= 4 N$
Number of tetrahedral voids $= 2 N$
Number of octahedral voids $= N$
Numberof'A' in the crystal = $\frac{N}{2} = \frac{4}{2} = 2$
Number of oxygen (O) atoms = $2 N = 2 \times 4 = 8$
The structure of bimetallic oxide = $A_{2} B_{4} O_{8} = A B_{2} O_{4}$

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Element 'B ' forms ccpstructure and 'A ' occupies half of the octahedral voids, while oxygen atoms occupy all the tetrahedral voids. The structure of bimetallic oxide is:

The correct option is B AB2O4The number of element ' B ' in the crystal structure =4N Number of tetrahedral voids =2N Number of octahedral voids =N Numberof'A' in the crystal = N2=42=2 Number of oxygen (O) atoms = 2N=2×4=8 The structure of bimetallic oxide = A2B4O8=AB2O4