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Question

Eliminate θ from the x = a secθ, y = b tanθ

A
x2a2y2b2 = 1
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B
x2a2+y2b2 = 1
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C
y2b2x2a2 = 1
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D
x2b2+y2b2 = 1
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Solution

The correct option is B x2a2y2b2 = 1
x=asecθxa=secθ
y=btanθyb=tanθ
1+tan2θ=sec2θ
1=tan2θ+sec2θ
x2a2y2b2=1

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