Question

Elimination reaction of $2-$ Bromopentane to form Pent-2-ene is:
(a) $\beta -$ Elimination reaction
(b) Follow Zaitsev rule
(c) Dehydrohalogenation
(d) Dehydration reaction

• A. (a), (b), (d)
• B. (a), (c), (d)
• C. (b), (c), (d)
• D. (a), (b), (c)

Answer 1

The correct option is D (a), (b), (c)


It is a $\beta -$ Elimination reaction since removed H was at $\beta$ position to the leaving group (here $B{r}^{-}$)

It follows Zaitsev rule to give more substituted alkene product.

Removal of both $H$ and $Br$ is name Dehydrohalogenation reaction.

It is not a dehydration reaction since there is no removal of water molecule.

Hence, option (c) is correct.